Represents a single Tree Node

Namespace: Visual3D.Scripting.Collections
Assembly: Visual3D.Scripting (in Visual3D.Scripting.dll) Version: 1.0.0.0 (1.0.0.0)

Syntax


	C#			Visual Basic

public class TreeNode<T> : IEnumerable<TreeNode<T>>, 
	IEnumerable

Public Class TreeNode(Of T) _
	Implements IEnumerable(Of TreeNode(Of T)), IEnumerable

Type Parameters


	All Members			Constructors			Properties			Methods

 Public

 Protected
 Instance

 Static 
 Declared

 Inherited
 XNA Framework Only 

 .NET Compact Framework Only 

	Member	Description
	TreeNode<(Of <(<'T>)>)>()()()()	Initializes a new instance of the TreeNode<(Of <(<'T>)>)> class
	TreeNode<(Of <(<'T>)>)>(T)	creates a new root node, and sets Value to value.
	Depth
	Detach()()()()	Detaches this node from it's parent. Postcondition: this is a root node.
	Find(Predicate<(Of <<'(T>)>>))
	GetElementPath()()()()
	GetEnumerator()()()()
	GetIndexPath()()()()
	GetIndexPathTo(TreeNode<(Of <<'(T>)>>))
	GetNodeAt(IEnumerable<(Of <<'(Int32>)>>))
	GetNodeAt(Int32)
	GetNodeAt(array<Int32>[]()[][])
	GetNodePath()()()()
	GetNodePathAsString(Char)
	GetNodePathAsString(Char, NodeToString<(Of <<'(T>)>>))
	GetValueEnumerator()()()()
	HasChildren	returns true if the node has child nodes. See also Implementation Note under this.Childs
	IsAncestorOf(TreeNode<(Of <<'(T>)>>))
	IsChildOf(TreeNode<(Of <<'(T>)>>))
	IsInLineWith(TreeNode<(Of <<'(T>)>>))
	IsRoot	returns true if this node is a root node. (Equivalent to this.Parent==null)
	Nodes
	Parent	returns the parent node, or null if this is a root node
	Remove()()()()	Removes the current node and all child nodes recursively from it's parent. Throws an InvalidOperationException if this is a root node.
	Root	The Root object this Node belongs to. never null
	Siblings
	Value

System..::..Object
Visual3D.Scripting.Collections..::..TreeNode<(Of <(<'T>)>)>